La siguiente reacción es altamente exotérmica: N2H4 + O2 → N2 + H2O ∆H= -622,4 Kj Cuánto calor se libera al producir 5 moles de nitrógeno.

-3112 kJ of heat will be released when 5 moles of nitrogen is produced.

Explanation:

We are given:

Moles of nitrogen = 5 moles

Given chemical reaction follows:

By stoichiometry of the reaction:

If 1 mole of nitrogen gas is produced, the heat released is -622.4 kJ

So, if 5 moles of nitrogen gas is produced, the heat released will be =

Hence, -3112 kJ of heat will be released when 5 moles of nitrogen is produced.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

2b2t

explanation:

2b2t