Chemistry, 28.06.2021 19:10 jonathanmagana112002

PLEASE HELP! Will give BRAINLIEST——List two possible steps where copper yield may be lost (why you may not get all the copper back at the end). Be specific about the steps and how they might lose the copper.

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Answer from: BigGirlsTheBest

Throughout the below section of explanation, the two possible steps are provided.

Explanation:

The CuO produced by that of the Cu(OH)2 heat treatment might cause reduced copper output, It's because of the technique of decanting. Following this Cu(OH)2, this would be translated into filtered parchment which causes certain contaminants to be added in the specimen and therefore doesn't decant throughout warming.When H2SO4 would be added to that same CuO that has been produced throughout the ending phase, CuSO4 has been accumulated that is transmitted as a way to solve something else that might reduce or lose copper content.

Answer from: Quest

They lack magnetic fields i do believe

Answer from: Quest

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form( $n_2$ ) .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

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PLEASE HELP! Will give BRAINLIEST——List two possible steps where copper yield may be lost (why you m...

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