How many kilograms of oseltamivir would be needed to treat all the people in a city with a population of 400000 people if each person consumes two oseltamivir capsules a day for 5 days? Express your answer to one significant figures and include the appropriate units.

300 kg

Explanation:

The give parameters obtained from a similar question are;

The mass of oseltamivir per capsule = 75 mg

The mass of oseltamivir required, M, is given as follows;

M = The mass of oseltamivir per capsule × The mass taken per person per day × 5 days × The number of people in the city

M = 0.75 mg/capsule × 2 capsule/(day·person) × 5 days × 400,000 people

M = 300,000,000 mg = 300 kg

answer is: empirical formula is tl₂o. if we use 100 grams of compound, tha:

m(tl) = 96.2%  · 100 g ÷ 100%.

m(tl) = 96.2 g.

n(tl) = m(tl)  ÷ m(tl). n(tl) = 96.2 g  ÷ 204.4 g/mol.

n(tl) = 0.47 mol. m(o) = 3.77 g. n(o) = m(o)  ÷ m(o). n(o) = 3.77 g  ÷ 16 g/mol. n(ag) = 0.235 mol. n(tl) . n(o) = 0.47 mol : 0.235 mol /0.235. n(tl) . n(o) = 2 : 1.

m(tl₂o) = 204.4 g/mol  · 2 + 16 g/mol = 424.8 g/mol.

m(compound) = 456. 8 g/mol - 424.8 g/mol = 32 g/mol ( 2 oxygens); tl₂o₃.