Chemistry, 29.06.2021 17:20 skylarladson2549

Check all that indicate a chemical change. Check all that apply. Group of answer choices aqueous solutions of silver nitrate and sodium chloride turn cloudy after mixing aqueous solutions of hydrochloric acid and sodium hydrogen carbonate produces bubbles on mixing Sodium hydroxide is mixed with water and the container feels warmer Water is added to orange juice is the color becomes lighter. No answer text provided. ice melts on a bench top at room temperature

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Answer from: claudr03

aqueous solutions of silver nitrate and sodium chloride turn cloudy after mixing aqueous solutions of hydrochloric acid and sodium hydrogen carbonate produces bubbles on mixing Sodium hydroxide is mixed with water and the container feels warmer

Explanation:

A chemical change involves the formation of new substances. Also heat is absorbed or released in a chemical change. Another name for a chemical change is a chemical reaction.

In the first case, a reaction of the sort;

AgNO3(aq) + NaCl(aq) ---> AgCl(s) + NaNO3(aq)

The cloudy solution is due to the formation of AgCl precipitate.

In the second case, a reaction of the sort;

HCl(aq) + NaHCO3(aq) ---> NaCl(aq) + CO2(g) + H2O(l)

The gas evolved is due to the formation of CO2 in the process. Heat is also evolved showing that it is a chemical change.

Answer from: Quest

answer: c. the experiment shows that the red substance experienced a chemical change.

explanation: chemical change is the change in which chemical composition of the substance changes. physical change is the change in which there is no change in chemical composition.

chemical changes are accompanied by following changes:

a) precipitate formation

b) energy is released or absorbed

c) formation of bubbles

d) change in color

as it is given that the red color has disappeared and there is production of gas, it means the red substance has undergone a chemical change.

Answer from: Quest

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = $25^oc$ = 298 k $)0^oc=273kelvins$

$o_3+3no\rightarrow 3no_2,\delta h_{reaction}=? [/)</p><p>[tex]\delta h_{no}=90.4kj/mol$

$\delta h_{no_2}=33.85kj/mol$

$\delta h_{o_3}=142.2kj/mol$

$\delta h_{reaction}=\sum \delta h_{products}-\sum\delta h_{reactants}=3\times\delta h_{no_2}-(3\times \delta h_{no}+\delta h_{o_3})$

$\delta h_{reaction}=33.85-(90.4+142.2)=-311.85kj/mol$

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

$v_{no}=12.00 l,v_{o_3}=8.50 l$

$pv_{no}=n_{no}rt=1atm \times 12.00 l=n_{no}\times 0.0821 atml/k mol \times 298 k$

$n_{no}=0.49 moles$

$pv_{o_3}=n_{o_3}rt=1atm \times 8.50 l=n_{o_3}\times 0.0821 atml/k mol \times 298 k$

$n_{o_3}=0.34 moles$

according to reaction 3 moles no are reacting with 1 mol of $o_3$ ,then 0.49 mol of no will react with $\frac{1}{3}\times 0.49$ moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and $o_3$ is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

$\delta h_{reaction}\times \text{moles of no}=-311.85kj/mol\times 0.49 mol=-152.80kj/mol$

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