A 50 ml solution suspected of containing ammonium ions was diluted to 250 mL A 50.0 mL aliquot of the diluted solution was analysed by Back-Titration. A 100 mL aliquot of a std 0.2005 M NaOH (MM = 40 g/mol) solution was added to the solution. The excess NaOH was back-titrated with 25.0 mL of a 0.1204 M std HCI (36/45 g/mol). The concentration of the ammonium ion (MM-18.04) in the initial sample solution (in g/dm) is:​

answer: option (b) is the correct answer.

explanation:

a covalent bond is formed by sharing of electrons. whereas polarity arises due to difference in electronegativity of two atoms.

therefore, more is the electronegativity of an atom which combines with the titanium, more readily it will induce a partial positive and negative charge.

thus, out of the given options fluorine is most electronegative and has an incomplete octet. therefore, it will readily combine with titanium to share the electrons and complete its octet.  

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"