Suppose 0.879 g of ammonia reacts with 28.5 mL of a hypobromite solution. Calculate the concentration of the hypobromite solution.

0.877 M

Explanation:

Number of moles of ammonia = 0.879 g /17 g/mol = 0.05 moles

The reaction equation is ;

2NH3 + OBr-→ N2H4 + Br- + H2O

2 moles of NH3 reacts with 1 mole of hypobromite

0.05 moles of NH3 reacts with 0.05 moles ×1 mole/2 moles

= 0.025 moles

Number of moles = concentration × volume

Concentration = Number of moles / volume

Concentration = 0.025 moles × 1000/28.5

Concentration = 0.877 M

2b2t

explanation:

2b2t

i think its 5049.

i hope this !