The osmotic pressure exerted by a solution is equal to the molarity multiplied by the absolute temperature and the gas constant . Suppose the osmotic pressure of a certain solution is measured to be at an absolute temperature of .

c = π/T*R

c = 0.199M

Explanation:

Is measured to be 5.1 atm at an absolute temperature of 312. K. Write an equation that will let you calculate the molarity c of this solution. Your equation should contain only symbols. Be sure you define each symbol other than R.

The osmotic pressure of a solution, π, is defined as:

π = c*T*R

As we know osmotic pressure π = 5.1atm, T = 312K and R = 0.082atmL/molK

we can replace in the equation as follows:

π= c*T*R

c = 5.1atm/312K*0.082atmL/molK

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole