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Chemistry, 09.07.2021 16:10 mecennabosaaen
At −12.6°C the concentration equilibrium constant Kc = 8.7 x 10^−5 for a certain reaction.
Here are some facts about the reaction:
The initial rate of the reaction is 11. mol·L^−1s^−1
If the reaction is run at constant pressure, 85.0 kJ/mol of heat are absorbed.
If the reaction is run at constant pressure, the volume increases by 12.%
Using these facts, can you calculate Kc at −23°C?
If you said yes, then enter your answer at right. Round it to 2 significant digits.
If you said no, can you at least decide whether Kc at −23.°C will be bigger or smaller than Kc at −12.6°C?
Required:
Using these facts, can you calculate Kc at —23C?
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At −12.6°C the concentration equilibrium constant Kc = 8.7 x 10^−5 for a certain reaction.
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