Study this chemical reaction: 2Fe(s) 3Pb(NO3)2(aq) 3Pb(s) 2Fe(NO3)3(aq) Then, write balanced half-reactions describing the oxidation and reduction that happen in this reaction.

Explanation:

2Fe(s) + 3Pb(NO₃)₂(aq) = 3Pb(s) + 2Fe(NO₃)₃(aq)

Half ionic reactions

2Fe(s) = 2Fe⁺³ + 6e

3Pb⁺² + 6e = 3 Pb(s)

In the first reaction Fe is oxidised to Fe⁺³ because its oxidation number increases from zero to + 3 .

In the second reaction , Pb⁺² is reduced to Pb (s) because its oxidation number is reduced from + 2 to zero.