Using the balanced equation below

27.99 g of CsF

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

CsF + XeF₆ —> CsXeF₇

Next, we shall determine the mass of CsF that reacted and the mass of CsXeF₇ produced from the balanced equation. This can be obtained as follow:

Molar mass of CsF = 133 + 19

= 152 g/mol

Mass of CsF from the balanced equation = 1 × 152 = 152 g

Molar mass of CsXeF₇ = 133 + 131 + (19× 7)

= 133 + 131 + 133

= 397 g/mol

Mass of CsXeF₇ from the balanced equation = 1 × 397 = 397 g

SUMMARY:

From the balanced equation above,

152 g of CsF reacted to produce 397 g of CsXeF₇.

Finally, we shall determine the mass of CsF required to produce 73.1 g of CsXeF₇. This can be obtained as follow:

From the balanced equation above,

152 g of CsF reacted to produce 397 g of CsXeF₇.

Therefore, Xg of CsF will react to produce 73.1 g of CsXeF₇ i.e

Xg of CsF = (152 × 73.1)/397

Xg of CsF = 27.99 g

Thus, 27.99 g of CsF is required for the reaction.

the answer is   c.) 1575 j.

explanation:

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