3. ¿Cuál de las siguientes operaciones es correcta para calcular el número de moles de hidrógeno necesarios para producir 6 moles de NH3 según la siguiente ecuación? 3H2+N2-> 2NH3 pliss necesito ayuda :( a)6molesNH3 x2molesNH3 /3molesH2
b) 6molesNH3 x3molesNH3 /2molesH2
c)6molesNH3 x3molesH2 /2molesNH3
d) 6 moles NH3 x 2 moles H2 / 3 moles NH3

the answer is d that is 6×2/3

the correct answer to this question is 2

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.