A sample of oxygen occupies 1.00 L. If the temperature remains constant, and the pressure on the oxygen is decreased to one third the original pressure, what is the new volume

3.00 L

Explanation:

P₁V₁ = P₂V₂

V₁ = 1.00 L

P₁ = (x) atm

P₂ = · (P₁) =

V₂ = unknown

(x atm)(1.00 L) = ( atm)(V₂)

divide both sides by ( atm)

( 1.00x )( ) = V₂

x cancels out

(1.00)(3) = V₂

V₂ = 3.00 L

level 4 to level 2 : ))

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.