Any shipment of peanuts that contains more than 25 ppb of this dangerous fungus is rejected. A company receives 24 t of peanuts to make peanut butter. What is the maximum mass, in g, of fungus that is allowed? Hint 1 t = 1000 kg.

0.60g of the fungus can be allowed

Explanation:

The maximum concentration of the fungus that can be allowed is 25 ppb, that is 25mg/t.

As the peanuts are 24t, the mass of fungus that can be allowed is:

24t * (25mg/t) = 600mg of the fungus can be allowed. In grams are:

600mg * (1g/1000mg) =

0.5g of toxin

Explanation:

ppb = mass of solute/ mass of solution x 10^9

ppb = mass of fungus/ mass of peanuts x 10^9

25ppb = (x/2 x 10^7g) x 10^9

x = (25)(2 x 10^7g)/ 10^9

x = 0.5g of toxin

x represented the unknown mass of solute (fungus), in which we solved for. We already knew we were using the ppb formula, which is mass of solute/ mass of solution x 10^9, because the question mentions that there are 25ppb of peanuts in the shipments. In the calculations, you can see that I substituted the mass of peanuts with 2 x 10^7g. I did this because the question mentions that there are 20t of peanuts and since each t = 1000kg, I multiped 20 x 1000 to get 20 000kg. In my formula for ppb, I know that I have to use grams of solution, not kilograms. Knowing this, we follow the formula for ppb and substitute our known values and solving for unknown values.

practical process described pest part of scientific investigation.

because practical knowledge is powerful then therotical knowledge.