Calculate the volume (in mL) of NO2 at 1 atm and 273 K obtained by treating 12.7 g of Cu with an excess of concentrated nitric acid from the following reaction: Cu(s) + HNO3(aq) —• Cu(NO3)2(aq) + H200(l) + NO2

1). 8960 2 ). 896

3 ). 89.3 4). 6900