A car of 1200 kg is moving with a speed of 36 Km/hr. It is stopped by applying brakes withion with in 5 seconds. Calculate the amount of force required to stop the car. ​

–2400 N

Explanation:

This is a physics question. However, the answer to the question is given below.

We'll begin by converting 36 Km/hr to m/s. This can be obtained as follow:

3.6 Km/hr = 1 m/s

Therefore,

36 Km/hr = 36 Km/hr × 1 m/s / 3.6 km/hr

36 Km/hr = 10 m/s

Thus, 36 Km/hr is equivalent 10 m/s.

Next, we shall determine the acceleration of the car. This can be obtained as follow:

Initial velocity (u) = 10 m/s

Final velocity (v) = 0 m/s

Time (t) = 5 s

Acceleration (a) =?

a = (v – u) / t

a = (0 – 10) / 5

a = – 10 / 5

a = –2 m/s²

Finally, we shall determine the force required to stop the car. This can be obtained as follow:

Mass (m) = 1200 Kg

Acceleration (a) = –2 m/s²

Force (F) =?

F = ma

F = 1200 × –2

F = –2400 N

NOTE: The negative sign indicate that the force is in opposite direction to the motion of the car.

b.

the accuracy of the data.