Under certain conditions, the substance mercury(II) oxide can be broken down to form mercury and oxygen. If 24.1 grams of mercury(II) oxide react to form 22.3 grams of mercury, how many grams of oxygen must simultaneously be formed? Grams oxygen

1.76 g

Explanation:

2HgO(s) ==> 2Hg(l) + O2(g)

Number of moles of Hg = 22.3 g/ 201g/mol

= 0.11 moles

From the reaction equation;

2 moles of Hg is formed alongside 1 mole of oxygen

Hence;

0.11 moles of Hg forms 0.11 moles × 1/2

= 0.055 moles of oxygen

Mass of oxygen formed = 0.055 moles of oxygen × 32g/mol = 1.76 g