What volume of 0.200 M Na2CO3 (Mm = 106 g/mol) solution contains 53.0 g of Na2CO3? Question 1 options:

0.200 L of solution

0.400 L of solution

0.500 L of solution

1.60 L of solution

2.50 L of solution

volume in Liter = 2.50 L

Explanation:

Given:

Na2CO3 = 0.2 M

Molar mass of Na2CO3 = 106 g/mol

Mass of Na2CO3 solution = 53 gram

Find:

Volume of Na2CO3

Computation:

Number of mol of Na2CO3  = (53 g) / (1.06 x 10² g/mol)

Number of mol of Na2CO3  = 0.5 mol

M = Number of mol / volume in Liter

0.2 = 0.5/ volume in Liter

volume in Liter = 0.5 / 0.2

volume in Liter = 2.50 L

idk

explanation: