Nguyên tố x trong tự nhiên có 2 đồng vị A1x và A2x với tỉ lệ số nguyên tử là 27:73. Số notron trong đồng vị A1x ít hơn đồng vị A2x là 2 hạt. Khi cho 12,708 gam x tác dụng với khí clo thu được 26,908 gam xcl2. Xác định số nguyên tử thu được của đòng vị A1x trong 71,54 gam x2o

first, consult an activity series chart to determine if al is more reactive than fe. it is, so it will replace the fe. now, one can continue with the problem.

next, make sure you have a correctly balanced equation.

3feo + 2al ==> 3fe + al2o3

now, determine which reactant (feo or al) is in limiting supply.

moles feo present = 125 g x 1 mole/71.8 g = 1.74 moles

moles al present = 25.0 g x 1 mole/26.98 g = 0.927 moles

since from the balanced equation, it take 3 mol feo for every 2 mol al, al will be limiting.

you can determine this simply by dividing moles of each by their coefficient in the balanced equation. for example: 1.74/3 = 0.58 and 0.927/2 = 0.464. al is less, so it is limiting.

finally, using the stoichiometry in the balanced eq. determine mass of fe that can be produced from 0.927 moles of al.

0.927 moles al x 3 moles fe/2 moles al x 55.8 g/mole = 77.6 g

може ли да зареждате повече информация, моля