Which statement describes a condensation reaction? A. monomers break away when one forms a double bond monomers break away with the addition of a water molecule.
B. Two monomers combine when one adds to the double bond of another.
C. Two monomers form a new bond with the loss of a water molecule .

The statement that describes a CONDENSATION reaction is that two monomers form a new bond with the loss of a water molecule . That is option C.

CONDENSATION REACTION involves the combination of two or more molecules(monomers) of water. In  reaction, a new bond is usually formed.

The characteristics of a condensation reaction includes:

A reaction is called a condensation reaction because a small molecule such as water is released as a byproduct.

A typical example of a condensation reaction is the condensation of amino acids to form dipeptide. The  −OH  from the carboxyl group of one amino acid combines with a hydrogen atom from the amine group of the other amino acid to produce water.

Therefore, the statement that describes a CONDENSATION reaction is that two monomers form a new bond with the loss of a water molecule. That is option C

Learn more about condensation here:

the electronic configuration of an atom with eight electrons is 1s²2s²2p⁴. the orbital diagrams are shown in the figure.

as per the hunds rule:

1. electrons tend to avoid being in the same orbital as per as practicable.

2. electrons in different orbitals of the same energy will have their spin parallel.

this can be illustrated from the multiplicity of the orbitals of the atom. as there are four electrons in the p orbital and p orbital has 3 sub-shells. the electrons can be fed in different ways as shown in the figure but the correct orbital diagram will be as per the hunds rule.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml