Cesium- is radioactive and has a half life of years. Calculate the activity of a sample of cesium-. Give your answer in becquerels and in curies. Round your answer to significant digits.

The question is incomplete, the complete question is;

Cesium-137 is radioactive and has a half life of 30. years. Calculate the activity of a 6.8 mg sample of cesium-137. Give your answer in becquerels and in curies. Round your answer to 2 significant digits Bq Ci

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Explanation:

The formula for activity is;

R= 0.693N/t1/2

N= 6.02 ×10^23 mol × 6.8 ×10^-3g/137 g/mol = 3 × 10^19

Substituting into the formula;

R= 0.693 × 3 × 10^19/30 years

R= 6.93 ×10^17 y^-1

In Bq;

6.93 ×10^17 y^-1 × 1.00y/3.16 ×10^7 seconds

= 2.19 ×10^10 Bq

In Ci;

2.19 ×10^10 Bq/3.7 ×10^10 Bq/Ci

= 0.59 Ci

every chemical equation adheres to the law of conservation of mass, which states that matter cannot be created or destroyed. therefore, there must be the same number of atoms of each element on each side of a chemical equation.

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