Calculate the weight of CuO formed when 200g of Copper carbonate is heated.(Atomic weight of Copper-64,Carbon-12,Oxygen-16)

129 g of CuO

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

CuCO₃ —> CuO + CO₂

Next, we shall determine the mass of CuCO₃ that decomposed and the mass of CuO produced from the balanced equation. This can be obtained as follow:

Molar mass of CuCO₃ = 64 + 12 + (16×3)

= 64 + 13 + 48

= 124 g/mol

Mass of CuCO₃ from the balanced equation = 1 × 124 = 124 g

Molar mass of CuO = 64 + 16

= 80 g/mol

Mass of CuO from the balanced equation = 1 × 80 = 80 g

SUMMARY:

From the balanced equation above,

124 g of CuCO₃ decomposed to produce 80 g of CuO.

Finally, we shall determine the mass of CuO produced by the decomposition of 200 g of CuCO₃. This can be obtained as follow:

From the balanced equation above,

124 g of CuCO₃ decomposed to produce 80 g of CuO.

Therefore, 200 g of CuCO₃ will decompose to produce

= (200 × 80)/124 = 129 g of CuO.

Thus, 129 g of CuO was obtained from the reaction.