What is the freezing point in °C) of a 0.743 m aqueous solution of KCI?
Enter your rounded answer with
3 decimal places.
K; for water = 1.86 °C/m

2.764 °C

Explanation:

ΔT = 2 x 1.86 C/m x 0.743m = 2.764C That means the freezing point of the solution is 2.764C less than the pure solvent (water)

it is to be noted that an alpha particle is an helium nucleus. so it contains 2 protons 2 neutrons and has a mass number of 4. when alpha decay particles are ejected from the nucleus it gets transformed into an atom which has atomic number less than 2 and a mass number less than 4.

an equation that could represent alpha decay is radium 226 decay of alpha particle forms radon 222.

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