Suppose there was a release of 1 mole of Alpha emission particle and 1 mole of Beta emission particles and both particles are accelerated to 20.50 MeV. What is the total energy in kJ/nuclei? Hint: 1 MeV = 1 x 106 eV and 1 eV = 1.602 X 10-19 J and 1 kJ = 1000 J, and finally in 1 mole there are Avogadro's number of particles which is 6.02214 x 1023 particles/mole. Report your answer in scientific notation to 2 decimal places for example 1.23 x 10-4 would be entered as 1.23 E-4. 238 92 U → 4 2 He + 234 90 Th and then 234 90 Th → 0
-1e + 234 91 Pa

Problem #3 (ch. 1, problem 15)the ideal gas law provides one way to estimate the pressure exerted by a gas on a container. the law isí‘ťí‘ť=푛푛푛푛푛푛푉푉more accurate estimates can be made with the van der waals equationí‘ťí‘ť=푛푛푛푛푛푛푉푉â’푛푛푟푟â’푞푞푛푛2푉푉2where the term nb is a correction for the volume of the molecules and the term an2/v2is a correction for molecular attractions. the values of a and b depend on the type of gas. the gas constant is r, the absolutetemperature is t, the gas volume is v, and the number of moles of gas molecules is indicated by n. if n = 1 mol of an ideal gas were confined to a volume of v = 22.41 l at a temperature of 0â°c (273.2k), it would exert a pressure of 1 atm. in these units, r = 0.0826.for chlorine gas (cl2), a = 6.49 and b = 0.0562. compare the pressure estimates given by the ideal gas law and the van der waals equation for 1 mol of cl2 in 22.41 l at 273.2 k. what is the main cause of the difference in the two pressure estimates, the molecular volume or the molecular attractions?

Calculate the molar mass of aluminum oxide (al2o3). express your answer to four significant figures.

Which statement best describes the flow of energy in this scenario