Consider the following system at equilibrium: N2 (g) + 3H2(g)--2NH3 (g) +92.94 kJ Which changes cause it to shift to the right (products):
1) Increase in temperature
2) decrease in temperature
3)increase in volume
4) decrease in volume
5) remove some NH3
6) addsome NH3
7) remove some N2
8) add some N2
a) 1,4,6,7
b) 2,3,5,8
c) 1,6,8
d) 1,3,5,7
e) 2,4,5,8

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.