A 4.00 g of solid copper metal react with 10.0 mL of concentrated nitric acid. Concentrated nitric acid is 12.0 M. The three products are copper(II) nitrate Cu(NO3)2, nitrogen monoxide (NO) and water. The NO gas collected, and it has a volume of 610 mL at STP conditions. Calculate the volume of NO gas should been formed theoretically. 3Cu (s) + 8HNO2 (aq) → 3Cu(NO3)2 (aq) + 2NO (g) + 4H20 (l)​

under a microscope, cancer cells may look very different from normal cells. they often have different sizes and some may be larger than normal while others are smaller. cancer cells are often abnormally shaped and the control centre of the cell (the nucleus) may have an abnormal appearance.

i think? ?

they are all solids.

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o