Chemistry, 03.09.2021 02:40 harrisakeeyah
Consider the following first order decomposition reaction with a half-life of 65 seconds at a given temperature:
N2O4 (g) → 2 NO2 (g)
Under these conditions, if a scientist begins the reaction with 4 atm of N2O4, how long will it take her to make 6 atm of NO2?
Answers: 2
Chemistry, 22.06.2019 04:30
What are the primary responsibilities of a chemical engineer involved in "r& d"? develop large scale manufacturing operations discover new products and processes training of new chemists determine products needed by consumers
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Chemistry, 22.06.2019 05:00
Given sno2 + 2h2 - sn + 2h20 tin oxide reacts with hydrogen to produce tin and water. how many moles of sno2 are needed to produce 500.0 grams of sn?
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Chemistry, 22.06.2019 10:50
A100 kmol/h stream that is 97 mole% carbon tetrachloride (ccl4) and 3% carbon disulfide (cs2) is to be recovered from the bottom of a distillation column. the feed to the column is 16 mole% cs2 and 84% ccl4, and 2% of the ccl4 entering the column is contained in the overhead stream leaving the top of the column. calculate the mass and mole fractions of ccl4 in the overhead stream, and determine the molar flow rates of ccl4 and cs2 in the overhead and feed streams. 12. mw_ccla- 153.82; mw_cs2-76.14.
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Chemistry, 22.06.2019 16:50
Answer asap need by wednesday morning explain how a buffer works, using an ethanoic acid/sodium ethanoate system including how the system resists changes in ph upon addition of a small amount of base and upon addition of a small amount of acid respectively. include the following calculations in your i. calculate the ph of a solution made by mixing 25cm3 0.1m ch3cooh and 40cm3 0.1m ch3coo-na+. [ka = 1.74 x 10-5 m] ii. calculate the ph following the addition of a 10cm3 portion of 0.08 m naoh to 500cm3 of this buffer solution. iii. calculate the ph following the addition of a 10cm3 portion of 0.08 m hcl to 200cm3 of the original buffer solution.
Answers: 1
Consider the following first order decomposition reaction with a half-life of 65 seconds at a given...
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