Express the frequency in inverse seconds. n=5-->n=1

Calculate the frequency of the light emitted when an electron in a hydrogen atom makes each of the following transitions.

n=4 -> n=3

n=5 -> n=1

n=5 -> n=4

n=6 -> n=5

when i did the first one i got 1.60*10^14, which was right, but when i did the second one the same way i got it wrong. could sombody show me how to do it so i can know what im doing wrong?

each time you need to use the same formula: delta E = Efinal -Einitial

Efinal = E1 = -2.18 x 10-18 J / 1^2

Einitl= E5 =  -2.18 x 10-18 J / 1^5

then use E = hv

u should get correct answer unless u r not making any calculation mistake

Explanation:

quartz

explanation:

"standard molar enthalpy:

h2o ( liquid water ) : - 285.8 kj/mole

h2o ( water vapor ) : - 241.8 kj / mole.

δhrxn = - 241. 8 - ( - 285.8 )= -241.8 + 285.8 = 44.0

answer: 44.0 kj"