Calculate the density of a proton, given that the mass of a proton is 1.0073 amu and the diameter of a proton is 1.71 x 10-15 m.

3.847 x 10^44

Explanation:

density is mass per unit volume.

we know the mass of the proton which is 1.0073 amu.

so density is mass/volume.

now we need to find the volume. a photon is spherical in shape. the equation for volume of a sphere is 4/3 πr^3.

we know the diameter which is 1.71 x 10^-15 m so the radius is half of that which is 8.55 x 10^ -16

now substitute the value of r in the volume of sphere equation. we get 4/3 π(8.55x10^-16)^3 = 2.618 x 10^-45

to find the density divide mass by volume.

1.0073 / 2.618 x10^-45 = 3.847 x 10^44 amu/m^3

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"