Part A. Deuterium-tritium fusion reaction. Given: energy released = 17.59 MeV per deuterium/tritium reaction pair (mass = 5 amu) Part B. Determine the energy released per kilogram of fuel used. Given MeV per reaction, calculate energy in joules per kilogram of reactants. Consider 1 mole of tritium plus 1 mole of deuterium yo be a mole of “reactions” (total molar mass = 5 grams)
Part C. Determine the mass of fuel required for the expected energy consumption in the United States for the next 10 years. Energy used per person per year in the United States = 3.5 x 10^11 joules. Base your calculations on a current population of 310,000,000

"record the time to complete a chemical reaction" would most likely be part of a lab procedure.

it is the most commonly accepted one

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole