An atomic emission spectrum of hydrogen shows three wavelengths: 121.5 nm,102.6 nm, and 97.23 nm

Assign these wavelengths to transitions in the hydrogen atom.

Drag the appropriate items to their respective bins.

We have that wavelengths to transitions in the hydrogen atom.

From the question we are told that

121.5 nm,102.6 nm, and 97.23 nm

Generally the equation for wavelength  is mathematically given as

Therefore

For nf=2,ni=1

For ni=1,nf=3

For ni=1,nf=4

Therefore

The Correct slots are

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a electronegativity decreases beacuse the size of nucleus is bigger.

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.