An oxide of P contains 50% by mass of P. Its Relative molecular mass is 64. The molecular formula of the oxide is (P=32; O=16) a. PO
b. PO2
c. P2O
d. PO3

B) PO2

Explanation:

first solve empirical formula

50%of P and 50%of O

P. O

50/32. 50/16

1.5. 3.0

1.5/1.5. 3.0/1.5

1. :. 2

Empirical formula=PO2

Molecular formula=PO2

(PO2)n= 64

(32+(16×2)=64

(32+32)n=64

64n=64

n= 1

anaphase.

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