BRAINLIEST ASAP Draw the electric field lines between a proton and an electron. According to Coulomb's law, how would the electrical force between these particles change if the product of their electrical charge increased?

Here we have to draw the electric field between two negatively charged particles and the effect of distance on it have to discuss.

The electric field between the two negatively charged particle are shown in the figure. There will be repulsion between the same charge particle. As the distance between the charged particle increases the force of repulsion will decreases.

The force of attraction between two charged particle was described by Coulomb, which is known as coulomb's inverse square law.

As per the law the force of attraction or repulsion between two charged particles is proportional to the multiplication of the charge and inversely proportional to the square of the distance between the particles.

Mathematically it can be represented as -

the force F ∞ q₁ × q₂ (q is the charge of the particles) and F ∞  (r is the distance between the two charge particles)

By combining F ∞  

Or, F = ∈⁻¹   (where ∈  = permittivity of the medium)

Thus as per the law as the distance (r) increases the force of repulsion between the two negatively charged particle will increase.

Thus the electric field between two negative charge particle is shown and  the effect of distance on it explained.

the dissociation of nickel hydroxide is follows:

the concentration of hydroxide ion is

the equilibrium constant value of nickel hydroxide is = 6.1 * 10^-^1^6 and thus equilibrium equation can be written as:

thus, concentration of ni is 0.23 * 10^-^4 mol /l

5.6⋅10−^19  j

do you need the explaination?