250 200
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Attempt due: Oct 10 at 11:59pm
12 Minutes, 9 Seconds
A
150
Temperature (Celsius)
100
B
D
50
SE
0
0
20
40
120
140
160
60 80 100
Time (min)
ry
The diagram above is the cooling curve of a certain chemical X
(molar mass=50 g/mol) with a mass of 100 grams. Based on the
data below, how much heat, in kJ, is released by this substance
during stage E?
]
ledia
(one decimal places for your answer)
otices
?
Help
specific heat of X(g): 0.89 J/g °C
specific heat of X(1): 1.4 J/g °C
specific heat of X(s): 2.6 J/g °C
enthalpy of melting: 4.6 kJ/mol
enthalpy of boiling: 24 kJ/mol

a plasma is a warm ionized gasoline consisting of approximately equal numbers of definitely charged ions and negatively charged electrons. the characteristics of plasmas are notably unique from the ones of ordinary neutral gases in order that plasmas are considered a awesome "fourth kingdom of remember."

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied