Microwave ovens emit microwave energy with a wavelength of .129 m. What is the energy of exactly one photon of this microwave radiation?

λ=Wavelength = .129 m = 0.129 m

E = energy = ?

h =Planck constant = 6.63 × 10^-34 J.s

f = frequency of photo/ electromagnetic radiation = c/λ

c = Speed of light in a vacuum = 3 × 10^8 m/s

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when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml