A student is trying to calculate the density of a ball. She already knows the mass, but she needs to determine the volume as well. Which of the following formulas can be used to calculate the volume of the ball? 1. V= 4/3 πr^3
2. V=1/3 πr^2h
3. s^3
4. πr^2h

The cone has a height of 10 and a diameter of 6. This means it has a radius of 3.

The volume of any cone is (1/3)πr2h. Therefore the volume of this cone would be (1/3)π(3)2(10) or 30π units3.

The hemisphere has a diameter of 6. This means it also has a radius of 3.

The volume of any sphere is (4/3)πr3. A hemisphere would be half that or (2/3)πr3. Therefore the volume of this hemisphere is (4/3)π(3)3 or 36π units3.The total volume would be 30π + 36π or 66π units3. The decimal approximation is 207.35 units3.

Explanation:

Cone: V = (1/3)πr2H

V = (1/3)π(3)2(10)

V = (1/3)π(90)

V = 30π

Hemisphere: V = (1/2)(4/3)πr3

V = (2/3)π(6)3

V = (2/3)π(216)

V = 144π

Total Volume = 30π + 144π = 174π

V ≈ 546.64 units3

no, i was listening to water by schoolboy q while and i saw this question

explenation:

water isn't wet. wetness is a description of our experience of water; what happens to us when we come into contact with water in such a way that it impinges on our state of being. we, or our possessions, 'get wet'. a less impinging sense experience of water is that it is cold or warm, while visual experience tells us that it is green or blue or muddy or fast-flowing. we learn by experience that a sensation of wetness is associated with water: 'there must be a leak/i must have sat in something.'