What is the equation for when an iron -53 goes through alpha decay and beta decay

Explanation:

β decay is a process in which a nucleus emits an electron.

The nuclear symbol for a β particle is

l

0

-1

e

.

In any nuclear equation, the sum of the subscripts (atomic numbers,

Z

) and the sum of the superscripts (atomic masses,

M

) must be equal on each side of the equation.

For the β decay of iodine 131, we have

131

53

I

→

l

M

Z

X

+

l

0

-1

e

Hence

131

=

M

+

0

, so

M

=

131

53

=

Z - 1

, so

Z

=

53

+

1

=

54

The element

X

with

Z = 54

is

Xe

.

So the equation is

131

53

I

→

131

54

Xe

+

l

0

-1

e

Note that in β decay, the product has the same mass number but an atomic number that has increased by 1.

c. 75.7

i think that is the right