Chemistry, 16.10.2021 03:50 savanah111
1. The equilibrium separation of the Rb and Cl ions in RbCl is about 0:267 nm. (a) Calculate the potential energy of attraction of the ions, assuming them to be point charges. (b) The ionization energy of rubidium is 4.18 eV, and the electron anity of Cl is 3.62 eV. Find the dissociation energy, neglecting the energy of repulsion. (c) The measured dissociation energy is 4.37 eV. What is the energy due to repulsion of the ions
Answers: 2
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1. The equilibrium separation of the Rb and Cl ions in RbCl is about 0:267 nm. (a) Calculate the pot...
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