Chemistry, 18.10.2021 07:20 kinkin79

Consider the titration of a 40.0 mL of 0.153 M weak acid HA (Ka = 2.7 x 10⁻⁸) with 0.100 M LiOH. a) Consider the titration of a 40.0 mL of 0.153 M weak acid HA (Ka = 2.7 x 10⁻⁸) with 0.100 M LiOH.
What is the pH of the solution before any base has been added?

b) Consider the titration of a 40.0 mL of 0.153 M weak acid HA (Ka = 2.7 x 10⁻⁸) with 0.100 M LiOH.
What would be the pH of the solution after the addition of 20.0 mL of LiOH?

c)Consider the titration of a 40.0 mL of 0.153 M weak acid HA (Ka = 2.7 x 10⁻⁸) with 0.100 M LiOH.
How many mL of the LiOH would be required to reach the halfway point of the titration?

d) Consider the titration of a 40.0 mL of 0.153 M weak acid HA (Ka = 2.7 x 10⁻⁸) with 0.100 M LiOH.
What is the pH of the solution at the equivalence point?

e) Consider the titration of a 40.0 mL of 0.153 M weak acid HA (Ka = 2.7 x 10⁻⁸) with 0.100 M LiOH.
What would be the pH of the solution after that addition of 100.0 mL of LiOH?

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Consider the titration of a 40.0 mL of 0.153 M weak acid HA (Ka = 2.7 x 10⁻⁸) with 0.100 M LiOH. a...

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