Chemistry, 18.10.2021 14:00 tiearahill2393
Hoà tan hết 5,28 gam hỗn hợp X và Cu bằng lượng dư dung dịch HNO3 loãng , thu được 1.792 lít NO ( đktc- sản phẩm khử duy nhất ) và dung dịch chứa m gam muối nitra
a) Tính khối lượng thành phần % về khối lượng mỗi kim loại trong hỗn hợp X ban đầu
b) Tính giá trị của m và số mol HNO3 đã phản ứng
Answers: 1
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Hoà tan hết 5,28 gam hỗn hợp X và Cu bằng lượng dư dung dịch HNO3 loãng , thu được 1.792 lít NO ( đk...
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