subject
Chemistry, 26.10.2021 01:00 fheight01

Fill un the blanks In enolase, the reaction mechanism uses lysine at position 345 as a base to remove a proton from 2-phosphoglycerate as the first step. However, this results in an increased negative charge on the carboxylate group of the resulting carbanion intermediate. There are Mg2 ions near the carboxylate part that function to the stability of the carbanion intermediate prior to glutamic acid at position 211, donating a proton to the intermediate in order to form the final product, phosphoenolpyruvate.

ansver
Answers: 1

Another question on Chemistry

question
Chemistry, 22.06.2019 20:30
Draw a line graph showing the relationship between temperature in kelvin as a function of kinetic energy.
Answers: 3
question
Chemistry, 23.06.2019 02:00
What is the mass of 0.750 mole of aluminum oxide, al2o3?
Answers: 1
question
Chemistry, 23.06.2019 05:30
For the reaction i2(g)+br2(g)←−→2ibr(g), kc=280 at 150 ∘c. suppose that 0.450 mol ibr in a 2.00-l flask is allowed to reach equilibrium at 150 ∘c. what is the equilibrium concentration of 2ibr, i2, br2
Answers: 1
question
Chemistry, 23.06.2019 06:20
What is the reaction between an acid and a base
Answers: 2
You know the right answer?
Fill un the blanks In enolase, the reaction mechanism uses lysine at position 345 as a base to rem...
Questions
Questions on the website: 13722363