PLEASE HELP M ASAP 50 PTS When methane, CHa, is combusted, it produces carbon dioxide, CO2, according to the unbalanced equation: CH4 + 02 - CO2 + H20.
Write the balanced equation for this reaction, and explain how it is possible for 10 grams of methane fuel to burn and emit 27 grams of carbon dioxide. Discuss whether or not this reaction obeys the law of conservation of mass.

The answerer is CH4 + 2O2 → CO2 + 2H2O

Explanation: }

Answer & Explanation:

The balanced equation for the reaction of combustion of methane:

CH₄ + 2O₂   →  CO₂ + 2H₂O

    reactants   products

C       1                 1

H      4                 4

O      4                 4

Moles of Methane = mass ÷ molar mass

                              = 10 g ÷ 16.04 g/mol

                              = 0.6234 mol

Since the mole ratio of CH₄ to CO₂ based on the balance equation is 1:1, then for every mole of  CH₄ reacted, 1 mole of CO₂.

∴ since mole of  CH₄ = 0.6324 mol

then moles of  CO₂  = 0.6324 mol

⇒ Mass of  CO₂ produced = moles × molar mass

                                            = 0.6324 mol × 44.01 g/mol

                                            = 27.83 g

                                            ≈ 27 g (as the question predicts).

Law of Conservation of Mass:

The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations.   According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

where is the following

explanation: