4. The 10 mL of hydrochloric acid contained 0.030 mol HCI. Perform stoichiometrie calculations to determine why the volume of the balloon with 0.15 g My, was about half
the volume of the balloon with 0.30 g Mg.
a. Make a BCA Table for the 2nd Mask, where 0.15 g Mg reacted with 0.030 mol HCI
Mg(s) + 2HC) -7 ng Cizcaq) + Hyg)
0-006757 0.30 0
B
C -0.0001757 -0.01234
+0.00617
0.00617
A 0 o