Activity 3: Mole to mole calculations: A mole ratio is the ratio between the number of moles of any two species involved in a chemical
reaction. It is used to convert the number of moles of a substance to the corresponding number
of moles of another substance in a chemical reaction.
Like balancing chemical equation, making stoichiometric calculations requires practice. Solve the
following mole to mole calculations and write your solutions and answer on the space provided.
1. How many moles of oxygen (O2) will be produced from 6.2 moles of water (H2O)?

2H2 + O2 2H2O



2. How many moles of carbon dioxide (CO2) will be produced by complete reaction of 2 moles
of glucose (C6H12O6)

C6H12O6 + 6O2 6CO2 + 6H2O



3. How many moles of ammonia (NH3) can be produced from 8 moles of hydrogen (H2)
reacting with nitrogen.

3H3 +N2 2NH3



4. Given a balanced chemical reaction. A) Calculate the number of moles of potassium
dichromate (K2Cr2O7) that will react with 2 moles of potassium iodide (KI). B) calculate
the number of moles of iodine (I2) that will be produced from 2 moles of potassium iodide
(KI)
K2Cr2O7 + 6KI +7H2SO4 Cr2(SO4)3 + 4K2SO4 + 3I2 +7H2O




4

5. How many molecules of water (H2O) can be produced by reacting 0.010 moles of oxygen
with hydrogen?

2H2 + O2 2H2O

You would be correct, boiling water does disinfect contamination.    the property of disinfecting means to kill  germs, bacteria and other pathogens or contamination  that might cause an infection or cause a person to become sickly. a couple methods of disinfecting are using soap, other cleaning supplies or by simply "boiling" the contaminate.  the reason why boiling water disinfects certain attributes is because some cells cannot survive the heat and pressure.

  remember that hf is only the energy of one photon. not two. not three. one.  1) 5.12 * 10^3 photons  find the energy of one photon, then determine how many photons are needed to reach the sensitivity.  e = hf  = (6.626 * 10^-34 js)(5.95 * 10^19 hz)  = 3.94247 * 10^-14 j per photon  (2.02 * 10^-10 j) / (3.94247 * 10^-14 j/photon) = 5123.69149 photons  round to three sig figs.  2) 5.77 * 10^-17 j  energy of pulse = energy per photon * number of photons  = hfn  = (6.626 * 10^-34 js)(1.66 * 10^13 hz)(5250)  = 5.774559 * 10^-17 j  round to three sig figs.  3) 4.07 * 10^8 kj/mol  10^12 pm = 1 m  c = fλ  f = c/λ  e = hf  = hc/λ  = [(6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.94 * 10^-12 m)](1 kj/1000 j)(6.02 * 10^23 photons/mol)  = 40702571.4 kj/mol  round to three sig figs.  4) 9.94 * 10^-1 m  e = hc/λ  λ = hc / e  = (6.626 * 10^-34 js)(3.00 * 10^8 m/s) / (2.00 * 10^-25 j)  = 0.9939 m  round to three sig figs.  5) 9.06 * 10^3 photons  energy of pulse = energy per photon * number of photons  number of photons = energy of pulse / energy per photon  = energy of pulse / (hf)  = (3.87 * 10^-13 j) / [(6.626 * 10^-34 js)(6.45 * 10^16 hz)]  = 9055.23695 photons  round to three sig figs.  6) 2.78 * 10^-15 j  this is problem 1, except in reverse.  sensitivity = minumum number of photons * energy per photon  = (5930)(6.626 * 10^-34 js)(7.077 * 10^14 hz)  = 2.78070758 × 10^-15 j  round to three sig figs.

The correct answer is b) false