The table shows data for two groups of plants one grown with fertilizer and the other without fetalizer was the mean height of the plant given fertilizer what affect does the vaule 35.6 have on the measures of central tendency for the data in the left column A. The mean will be higher than the mode but lower then the median.

B. The mean will be lower than the median and the mode

C. The mean will be higher than the median but lower than the mode

D. The mean will be higher than the median and the mode

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

sure im new too!

explanation: