Tính pH của các dung dịch sau: a. 11,2 g KOH trong 2 lit dung dịch
b. CH3COOH 0,001M biết Ka = 1,85.10-5
c. NH3 10-4 M biết pKb = 4,74
d. NH3 0,01M và NH4Cl 10-4 M, biết Ka = 1,8.10-5

the answer is true. hope it .

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2