Hents Part E
Calculate the amount of heat lost by the object(s) after being transferred from cup 1 to cup 2. Remember that a
decrease in temperature is a negative change. Use the data recorded in parts A and C and the formula for heat
transfer, Q = mCAT.
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2060.775 J

Explanation:

From the question given above, we obtained the following data:

Specific heat capacity (C) = 0.129 J/g°C

Mass (m) = 355 g

Initial temperature (Tᵢ) = 95 °C

Final temperature (Tբ) = 140 °C

Heat (Q) tranfered =?

We can calculate the amount of heat transferred by using the following formula:

Q = mC(Tբ – Tᵢ)

Q = 355 × 0.129 (140 – 95)

Q = 45.795 × 45

Q = 2060.775 J

Thus, 2060.775 J of energy was transferred.

Explanation:

Hope this helps:)

Your correct !!