Given the balanced chemical equation: 4 Fe + 3 O2 > 2 Fe2O3

How many moles of iron(III) oxide, Fe2O3 , will be produced if 12 moles of iron, Fe, are consumed.

6 moles

Explanation:

Looking at the coefficient of the reactants/ products, the ratio of Fe consumed to Fe₂O₃ produced is 4: 2.

Fe: Fe₂O₃

= 4: 2

= 2: 1

This means that the amount of Fe₂O₃ produced is half the amount of Fe consumed, in terms of moles.

Given that 12 moles of Fe are consumed,

amount of Fe₂O₃ produced

= 12 ÷2

= 6 moles

see explanation

Explanation:

4Fe +3O22Fe2O3

if we have 12 moles of Fe, we have 3X4 mole of Fe

but since 4 moles of Fe produce 2 moles of Fe2O3,6 then 3X 4 moles of Fe produce 3X2 moles of Fe2O3 or

6 moles.

One mole of Fe2O3 has a molar mass of (56X2) +(3X16) = 112+48 = 160

One mole Fe2O3 has a molar mass of 160 gm

6 moles of Fe2O3 have a mass of 160 X6 =960 gm