A sample of BrF5 contains 2.68*10^22 atoms of F. What is the mass of the sample? Give answer to the correct number of significant figures, including units with no spaces. 1mol=6.022*10^23particles

Adozen is 1221/12 = 1.751.75 x 12 = 21therefore, 1.75 is the answer.

It will fall off and tip over. 

Answerthe half-reaction having the greatest tendency to occur at the anode:     i₂(aq) + 2e⁻  ⇄ 2i⁻  ;   e = +0.53 v======oxidation occurs at the anode. we must therefore find the half-reaction with the greatest tendency to oxidize.the given values of e are reduction potentials (the form of the half-reactions are of reduction).the lower the reduction potential, the higher the potential to oxidize. the half-cell with the lowest reduction potential will have the greatest tendency to oxidize at the anode.the half-reaction having the greatest tendency must be    i₂(aq) + 2e⁻  ⇄ 2i⁻    e = +0.53 vbecause its reduction potential is the lowest out of the three.