a 9.70 dm3 sample of carbon dioxide at a tempature of 79.8 C° cools to -23.4C° what would the new volume be

so what is the problem with your lab report and whats the subject of the lab report? i will you

b. is the answer hoped i        

answer: mole of the gas

answer: mole of the gasexplanation:

percent abundance for cu-63 can be shown as:

63 x + 65 (1-x) = 62.9296

65 - 62.9296 = 2 x

x = 1.035

thus, percent abundance for cu-63 is 1.035

percent abundance for cu-65 can be shown as:

63 x + 65 (1-x) = 64.9278

65 - 64.9278 = 2 x

x = 0.0361

thus, percent abundance for cu-63 is 0.0361

the mass spectrum of cu-63 showing the intense peak as, this isotope is found in nature more abundantly around 92.38 % in comparison to cu-65 which is found 62.58 % naturally