A sample of a compound contains 32. 0 g C and 8. 0 g H. Its molar mass is 30. 0 g/mol. What is the compound’s molecular formula? CH3 CH4 C2H4 C2H6.

The ratio is 3: 2. i.e. c.

Answer:

it was spontaneous.

explanation:

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Reaction involved in present system is :   c12h22o11 + h2o → 2 c6h12o6the reaction system is obeying following rate law:   rate = k[c12h22o11]thus, it is a first order reaction.now, for 1st order reactionrate constant (k) =  given: initial conc. = 3.0 g, final conc. = 2.7 g, t = 2.5 h∴rate constant (k) =  ∴ k = 0.04215 h-1now, for 1st order reaction, half life = 0.693/k = 0.693/0.04215 = 16.4 hthus correct answer is option b